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Question

The standard enthalpies of formation of CO2(g), H2O(l) and glucose(s) at 25C are 400 kJ/mol, 300 kJ/mol and 1300 kJ/mol, respectively. The standard enthalpy of combustion per gram of glucose at 25C is


A

+ 2900 kJ

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B

−2900 kJ

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C

−16.11 kJ

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D

+16.11 kJ

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Solution

The correct option is C

−16.11 kJ


The standard enthalpy of the combustion of glucose can be calculated by the equ.

C6H12O6(s) + 6O2(g) 6CO2(g) + 6H2O(l)

ΔHc = 6 × ΔHf(CO2) + 6 × ΔHf(H2O) ΔHf[C6H12O6]

ΔH0 = 2900180 = 16.11 kJ/gm


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