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Question

The standard oxidation potentials Eo, for the half cell reactions are given as
ZnZn2++2e, E=+0.76 VFeFe2++2e, E=+0.41 V
The EMF for the cell reaction,
Fe2++ZnZn2++Fe is:

A
0.35 V
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B
+0.35 V
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C
1.17 V
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D
1.17 V
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Solution

The correct option is B +0.35 V
Oxidation potentials are given for the two half cell reactions:
FeFe2++2e, E=+0.41 V...........(i)
ZnZn2++2e, E=+0.76 V............(ii)
Subtracting (ii) from (i), we can have the desired reaction
Fe2++ZnZn2++Fe, E=(0.760.41) V =+0.35 V

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