The standard reduction potential Eo for half reaction are- Zn-Zn2-2e- Eo-0-76V Fe-Fe2-2e- Eo-0-41VThe EMF of the cell reaction is- Fe2-Zn-Zn2-Fe

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Standard XII

Chemistry

Nernst Equation

The standard ...

Question

The standard reduction potential $E^{o}$ for half reaction are:

$Z n \to {Z n}^{2 +} + 2 e^{-}; E^{o} = + 0.76 V$
$F e \to {F e}^{2 +} + 2 e^{-}; E^{o} = + 0.41 V$

The EMF of the cell reaction is:
${F e}^{2 +} + Z n \to {Z n}^{2 +} + F e$

- 0.35 V

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+ 0.35 V

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+ 1.17 V

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- 1.17 V

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Solution

The correct option is B $+ 0.35 V$
$Z n ⟶ {Z n}^{2 +} + 2 e^{-}; E_{o x i}^{o} = + 0.76 V$
or $E_{r e d}^{o} = - 0.76 V$

$F e ⟶ {F e}^{2 +} + 2 e^{-}; E_{o x i}^{o} = 0.41 V$
or $E_{r e d}^{o} = - 0.41 V$

$∴$ $E_{c e l l}^{o} = E_{c a t h o d e}^{o} (R P) - E_{a n o d e}^{o} (R P)$
$= - 0.41 - (0.76)$
$= 0.35 V$

Hence, option B is correct.

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Similar questions

Q. The standard reduction potential

E^{o}

for half reactions are,

Z n \to Z n^{2 +} + 2 e^{-}; E^{o} = - 0.76 V

F e^{2 +} + 2 e^{-} \to F e; E^{o} = + 0.41 V

The emf of the cell reaction;

F e^{2 +} + Z n \to Z n^{2 +} + F e

is:

Q. The standard reduction potential

E^{o}

for the half reactions are as

Z n ⟶ {Z n}^{2 +} + 2 e^{-}

;

E^{o} = + 0.76 V

F e ⟶ {F e}^{2 +} + 2 e^{-}

;

E^{o} = + 0.41 V

The emf for cell reaction,

{F e}^{2 +} + Z n ⟶ {Z n}^{2 +} + F e

, is

The standard reduction potentials, $E^{\circ}$ , for the half-reactions are as $Z n = Z n^{2 +} + 2 e$ , $E^{\circ}$ = + 0.76 V and $F e = F e^{2 +} + 2 e$ , $E^{\circ}$ = + 0.41 V. The e.m.f. for the cell reaction, $F e^{2 +} + Z n = Z n^{2 +} + F e$ is