Question

The states of hybridization of boron in boric acid ($H_{3}B{O}_3$) and ($B{F}_3$) are respectively

• A. and
• B. and
• C. and
• D. and

Answer 1

The correct option is C

and

No of hybrid orbitals in $H_{3}B{O}_3$ = group no. of B + no. of monovalent atoms/2

= 3 + $\frac{3}{2}$ = $\frac{6}{2}$ = 3 so ${sp}^2$