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Question

The steam point and the ice point of a mercury thermometer are wrongly marked as $$92^oC$$ and $$2^oC$$ respectively. The correct temperature read by this thermometer is:


A
2oC
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B
5oC
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C
10oC
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D
20oC
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Solution

The correct option is D 20$$^{o}$$C
$$ \dfrac{x-2}{92-2} = \dfrac{c-0}{100-0}$$
Temperature measued by this thermoomeeter = $$20^\circ$$
$$= \dfrac{20-2}{90} = \dfrac{c}{100}$$
$$c = 20^\circ c$$
Hence (D) is correct answer

Physics

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