Question

# The steam point and the ice point of a mercury thermometer are wrongly marked as $$92^oC$$ and $$2^oC$$ respectively. The correct temperature read by this thermometer is:

A
2oC
B
5oC
C
10oC
D
20oC

Solution

## The correct option is D 20$$^{o}$$C$$\dfrac{x-2}{92-2} = \dfrac{c-0}{100-0}$$Temperature measued by this thermoomeeter = $$20^\circ$$$$= \dfrac{20-2}{90} = \dfrac{c}{100}$$$$c = 20^\circ c$$Hence (D) is correct answerPhysics

Suggest Corrections

0

Similar questions
View More

People also searched for
View More