Question

The straight line $(x-2)+(y+3)=0$ cuts the circle ${(x-2)}^2+{(y+3)}^2=11$ at

• A. no points
• B. two points
• C. one point
• D. None of these

Answer 1

Answer: (B)

two points

Equation of circle $(x-2{)}^2+(y+3{)}^2=0$

Equation of Line $(x-2)+(y+3)=0$

It is clear line passes through $(2,-3)$ which is the centre of the circle

So the line touches other circle at $2$ points