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Question

The straight lines x + y = 4 3x + y = 4, x + 3y - 4 = 0 form a triangle which is -

A
Isoceles
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B
Equilateral
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C
Right angle
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D
None of these
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Solution

The correct option is D Isoceles
x+y=4
and 3x+y=4
x=0,andy=4
x+y=4
and x+3y=4
x=4
and y=0
Similarly when
3x+y=4
and x+3y=4
thenx=1andy=1
A=(0,4),B=(1,1)andC=(4,0)
AB=(01)2+(41)2
=10
and BC=(14)2+(10)2
=10
AB=BC
Δ is isoceles.

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