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Question

The streets of a city are arranged like the lines of a chess board. There are 5 streets running North to South and 3 streets running East to West. The number of ways in which a man can travel from NW to SE corner going the shortest possible distance is:

A
6!4!2!
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B
56
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C
8!5!3!
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D
15
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Solution

The correct options are
A 6!4!2!
D 15
Here we should go (31) steps to east and (51) steps to south.

So the total steps we should go=5+32 ways

Hence the total number of ways = 5+32C51.31C31
=6C4.2C2
=6!4!2! (2C2=1)
=6×5×4!4!2!=6×52=15 ways.

Option (a) and (d) are correct.

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