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Question

The successive terms of an A.P. are a1,a2,a3,.Ifa6+a9+a12+a15=20, then 20r=1ar= 
  1. 75
  2. 100
  3. 120
  4. 150


Solution

The correct option is B 100
Let d be the common difference a6+a9+a12+a15=20a1+5d+a1+8d+11d+a1+14d=204a1+38d=202a1+19d=10S20=[2a+19d]=10×10=100

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