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Question

The sum of 3 consecutive multiples of 8 is 888. Find the multiples

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Solution

Let 3 consecutive multiple of 8
8x,8(x+1),8(x+2)
Sum=8x+8(x+1)+8(x+2)=888
8(x+x+x+1+2)=888
3(x+1)=111
x+1=1113
x+1=37
x=36
First multiple =8x=8×36=288
Second =8(x+1)=8×37=296
Third =8(x+2)=8×38=304

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