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Question

The sum of 40 terms of an A.P. whose first term is 2 and common difference 4, will be

A
3200
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B
1600
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C
200
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D
2800
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Solution

The correct option is A 3200
We know the formula:
Sn=n2[2a+(n1)d]
Here, n=number of terms=40
a=first term=2
d=common difference=4
So, putting the above values in formula we get,
S40=402[2(2)+(401)4]=20[4+39×4]=20[4+156]=20×160=3200
Sum of 40 terms=3200

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