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Question

The sum of a,b,c is 264. If a be twice as b and c be one – third of a, then b is:


  1. 48

  2. 54

  3. 72

  4. 84

  5. 91


Solution

The correct option is C

72


Let the second number be x.

Then, first numbe = 2x and third number = 2x3.

2x+x+2x3=26411x3=264x=(264×311)=72

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