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Question

The sum of a two-digit number and the number obtained by reversing the order of its digits is 121, and the two digits differ by 3. Find the number.


Solution

Let no at ones= x 
Let no. at tens=10(x+3)
                       =10x+ 30
New no.reversing the order of the digit
Let no. at ones place x+3
let no. at tens place 10x
(10x +30+x )+ (10x + x +3)= 121
22x=88
x = 8822
x=4
The original no. is 74
The new no. is 47


 

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