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Question

The sum of all interior angles of a regular polygon is 1080. What is the measure of each of its interior angles ?

(a) 135 (b) 120 (c) 156 (d) 144


Solution

Sum of all interior angles of polygon = 1080 Let n be the number of sides, then (2n-4)× 90 = 1080 2n-4=108090 = 12 2n=12+4=16 n = 162 = 8 Each angle = 10808=135


Mathematics
Secondary School Mathematics VIII
Standard VIII

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