The sum of direction cosines of the given vector 6^i+2^j−3^k is
A
57
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B
37
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C
67
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D
1
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Solution
The correct option is A57 Let →a=6^i+2^j−3^k
Direction ratios of →a are 6,2,−3 ⇒ Direction cosines of the given vector are given by 6√62+22+(−3)2,2√62+22+(−3)2,−3√62+22+(−3)2
or, 67,27,−37 ∴ The sum of direction cosines is 57.