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Question

The sum of first 16 terms of the A.P.: 10, 6, 2, ..., is
(a) –320
(b) 320
(c) –352
(d) –400

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Solution

The given A.P. is:
10, 6, 2, ...,

First term = a = 10
Common difference = d = 6 − 10 = −4

S16=1622a+16-1d =82a+15d =8210+15-4 =820-60 =8×-40 =-320

​Hence, the correct option is (a).

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