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Question

 The sum of first 16 terms of the AP 10, 6, 2, ... is
(a) 320    (b) -320   (c) -352   (d) -400
 


Solution

The formula for the sum of first n terms of a AP is n/2(2a+(n-1)d)
here n=16 a=10 d=6-10=2-6=-4
so sum of first 16 terms=16/2(2·10+(16-1)·-4)
=8(20+15·-4)
=8(20-60)
=8(-40)
=-320
therefore the option is A

 

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