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Question

The sum of (n+1) terms of 11+11+2+11+2+3+.......... is


A

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B

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C

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D

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Solution

The correct option is D


Tn=1[n(n+1)2]=2[1n1n+1]

put n=1,2,3,.........,(n+1)

T1=2[1112],T2=2[1213],...........,

Tn+1=2[1n+11n+2]

Hence sum of (n+1) terms = n+1k=1Tk

Sn+1=2[11n+2] Sn+1=2(n+1)n+2


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