The sum of the area of two circles which touch each other externally is 153π. If the sum of their radii is 15, the ratio of the larger to the smaller radius is
Let r1 and r2 be the radii:
Given A1+A2=153π
πr21+πr22=153π
r21+r22=153
And
r1+r2=15
SOBS
r21+r22+2r1r2=225
2r1r2=225−153
r1r2=36
r1–r2=√(r21+r22)2−4r1r2=√225−144=9
⟹r1=12,r2=3
⟹r1r2=4