Question

The sum of the digits of a 3 digit number is subtracted from the number. The resulting number is always

• A. divisible by 6
• B. not divisible by 6
• C. divisible by 9
• D. not divisible by 9

Answer 1

The correct option is C divisible by 9

Let three digit number be $100+10y+z$
$\therefore (100x+10y+z)-(x+y+z)=99x+9y=9(11x+y)$
which is already divided by 9.