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Question

The sum of the real solutions of the equation 52x2−2.5x2+x+1−3.52x+3=0, is

A
1
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B
2
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C
3
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D
4
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Solution

The correct option is A 1
52x22.5x2+x+13.52x+3=0
Dividing the expression by 52x,
52x22x10.5x2x3.53=0
Let, 5x2x=t
On substitution,
t210t375=0
(t25)(t+15)=0t=25,15
But, t>0, hence we reject t=15
5(x2x)=52x2x=2
x2x2=0(x2)(x+1)=0
x=2,1
Sum of the real roots is =1.

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