The sum of the series 1+45+752+1053+…∞ is
Let,
S=1+45+752+1053+…∞
Then,
15S=15+452+753+…∞
⇒S(1−15)=1+3[15+152+153+…∞]
⇒45S=1+3×1/51−(1/5)=1+34=74
⇒S=3516