The sum of the series 12-1 - 1- 22-1 - 2- 3-1 - 3- - n2-1- n- is

The correct option is B n· ( n+1 )! T_n=(n^2+1)n! =[(n+1)^2 2n]n! =(n+1)^2.n! 2n.n! =(n+1)(n+1)! 2n.n! Hence ∑ T_n=∑_n=1 ^n=n n ...

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Sum of Product of Binomial Coefficients

The sum of th...

Question

The sum of the series $(1^{2} + 1) \cdot 1! + (2^{2} + 1) \cdot 2! + (3 + 1) \cdot 3! + \cdot \cdot + (n^{2} + 1 \cdot n!)$ is

(n + 1) \cdot (n + 2)!

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n \cdot (n + 1)!

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(n + 1) \cdot (n + 1)!

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none of these

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