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Question

The sum of three consecutive multiples of $$11$$ is $$363$$.Find these multiples.


Solution

Let the three consecutive multiples of $$11$$ be $$x,\,x+11$$ and $$x+22$$
$$x+x+11+x+22=363$$
$$\Rightarrow\,3x+33=363$$
$$\Rightarrow\,3x=363-33=330$$
$$\Rightarrow\,x=\dfrac{330}{3}=110$$
$$\therefore\,x=110$$
Hence, the three consecutive multiples are $$110,121,132$$

Maths

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