Question

# The sum of three consecutive multiples of $$11$$ is $$363$$.Find these multiples.

Solution

## Let the three consecutive multiples of $$11$$ be $$x,\,x+11$$ and $$x+22$$$$x+x+11+x+22=363$$$$\Rightarrow\,3x+33=363$$$$\Rightarrow\,3x=363-33=330$$$$\Rightarrow\,x=\dfrac{330}{3}=110$$$$\therefore\,x=110$$Hence, the three consecutive multiples are $$110,121,132$$Maths

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