CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

The sum of three numbers in A.P. is 12 and the sum of their cubes is 288. Find the numbers.


Solution

Let the numbers be (a - d), a, (a + d)
Sum = a - d + a + a + d = 12
3a=12a=4
Also, (ad)3+a3+(a+d)3=288
a3d33a2d+3ad2+a3+a3+d3+3a2d+3ad2=2883a3+6ad2=2883(4)3+6×4×d2=288192+24d2=28824d2=96d2=4d=±2
When a = 4, d = 2, the numbers are 2, 4, 6
When a = 4, d = -2, the numbers are 6, 4, 2


Mathematics
RD Sharma
Standard XI

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
Same exercise questions
View More


similar_icon
People also searched for
View More



footer-image