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Question

The sum of two number is 40. If the smaller number is doubled, it becomes 14 more than the larger number. Find the numbers

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Solution

Let the larger number be x
and smaller number be y
As per the question, we have
x+y=40 ....(1)
and 2y=14+x ....(2)
Therefore, y=14+x2 ....(3)
Substitute this value of y in equation (1), we get
x+14+x2=40
2x+14+x=80
3x=8014
3x=66
x=22
Put this value of x in equation (3),
y=14+222
y=18
therefore, the two numbers are 22 and 18.

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