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Question

Sum of two numbers is 4 more than the twice of difference of the two numbers. If one of the two numbers is three more than the other number, then find the numbers.
 


  1. (132,72)

  2. (1, 3)

  3. (45,3)

  4. (1, 2)


Solution

The correct option is A

(132,72)


Let one number be x and other be y.

1st case:
x+y=4+2(xy)
x+y=4+2x2y
x3y+4=0    ...(i)

2nd case:
x=3+y    ...(ii)

On substituting (ii) in (i), we get
(3+y)3y+4=0
y=72

On substituting the value of y in (ii), we get
x=3+72=132

Therefore, the numbers are 132 and 72.

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