Question

# The surface of the metal is illuminated with the light of 400 nm. The kinetic energy of the ejected photoelectrons was found to be 1.68 eV, the work function of metal is :

A
1.51 eV
B
1.42 eV
C
3.0 eV
D
1.68 eV

Solution

## The correct option is B 1.42 eVAs we know,           $${\phi}_0=\dfrac{hc}{\lambda}-E_k$$ (Einstein's equation)           $$=\dfrac{1240 eVnm}{400 nm}-1.68 eV$$            $$=3.1-1.68=1.42 eV$$Physics

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