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Question

The surface of the metal is illuminated with the light of 400 nm. The kinetic energy of the ejected photoelectrons was found to be 1.68 eV, the work function of metal is :


A
1.51 eV
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B
1.42 eV
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C
3.0 eV
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D
1.68 eV
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Solution

The correct option is B 1.42 eV
As we know, 

          $${\phi}_0=\dfrac{hc}{\lambda}-E_k$$ (Einstein's equation)

           $$=\dfrac{1240 eVnm}{400 nm}-1.68 eV$$

            $$=3.1-1.68=1.42 eV$$

Physics

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