CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The system of equations kx+y+z=1,x+ky+z=k and x+y+zk=k2 has no solution if k is equal to

A
2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 2
Given system of equations
kx+y+z=1x+ky+z=kx+y+zk=k2
Now,
D=∣ ∣k111k111k∣ ∣=0k(k21)(k1)+(1k)=0(k1)(k2+k11)=0(k1)(k2+k2)(k1)(k1)(k+2)=0k=1,k=2
For k=1 equations becomes identical, so k=2 for no solution.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Tango With Straight Lines !!
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon