CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

The system shown in fig. is released from rest with mass 2 kg in contact with the ground. Pulley and spring are massless, and friction is absent everywhere. The speed of 5 kg block when 2 kg block leaves the contact with the ground is (force constant of the spring k=40Nm1andg=10ms2 ).



Solution

The correct option is D


Let x be the extension in the string when 2 kg block leaves the contact with ground. Then tension in the spring should be equal to weight of 2 kg block:

Kx=2gorx=2gK=2×1040=12m

Now from conservation of mechanical energy,

mgx=12Kx2+12mv2

=2gxKx2m=2×10×12404×5=22ms1

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
View More


People also searched for
View More



footer-image