Question

The table below gives the population (in thousands) of ten species (A-J) in four areas (I-IV) consisting of the number of habitats given within brackets against each. Study the table and answer the question which follows
$\begin{array}{cccccccccccc}\text{Area and}& \text{Species and their}& & & & & & & & & & \\ \text{number of}& \text{population (in}& & & & & & & & & & \\ \text{habitats}& \text{thousands)}& & & & & & & & & & \\ & \text{in the Area}& A& B& C& D& E& F& G& H& I& J\\ \text{I}\left(11\right)& & 23& 1.2& 0.52& 6.0& -& 3.1& 1.1& 9.0& -& 10.3\\ \text{II}\left(11\right)& & 10.2& -& 0.62& -& 1.5& 3.0& -& 8.2& 1.1& 11.2\\ \text{III}\left(13\right)& & 11.3& 0.9& 0.48& 2.4& 1.4& 4.2& 0.8& 8.4& 2.2& 4.1\\ \text{IV}\left(13\right)& & 3.2& 10.1& 11.1& 4.8& 0.4& 3.3& 0.8& 7.3& 11.3& 2.1\end{array}$
Which area out of I to IV shows maximum species diversity? (correct answer + 2, wrong answer - 0.50)

• A. II
• B. III
• C. IV
• D. I

Answer 1

The correct option is C IV

In the given table, the area ‘IV’ has maximum species diversity, as there are 10 species (A-J) reside in 12 habitats, while in area ‘III’, the 10 species reside in 13 habitats, so exhibit less diversity than area ‘IV’.

Area 'I' has only 8 kinds of species with 11 habitats and area 'II' has the least species diversity with only 7 kinds of species with 11 habitats.