    Question

# The table below shows the daily expenditure on food of 30 households in a locality: Daily expenditure (in Rs.)Number of households100−1506150−2007200−25012250−3003300−3502 Find: (a) mean of daily expenditure on food. (b) median of daily expenditure on food.

Open in App
Solution

## Let assumed mean A = 225 and h = 50 Daily expenditure (in Rs.)FrequencyMid- value(xi=l+h2)ui=xi−Ahfiuicf100−1506125−2−126150−2007175−1−713200−250122250025250−30032751328300−35023252430∑(fiui)=−12 = x¯=A+h(∑fiui/N) (i) Mean = A + h ∑fiuiN = 225 + 50× −1230 = 225 - 20 = 205 (ii) N = 30,N2 = 15 Cumulative frequency just after 15 is 25 Corresponding frequency interval is 200 - 250 Median class is 200 - 250 Cumulative frequency c just before this class = 13 So I = 200, f = 12, N2 = 15, h = 50, c = 13 Therefore, Median = l + hN2−cf = 200 + 50×15−1312 = 200 + 50 × 16 = 200 + 8.333 =208.33 Hence, Mean = 205 and Median = 208.33  Suggest Corrections  7      Similar questions  Related Videos   Mean
MATHEMATICS
Watch in App  Explore more