Question

# The taxi charges in Hyderabad are fixed, along with the charge for the distance covered. For a distance of $$10km$$, the charge paid is Rs. $$220$$. For a journey of $$15km$$, the charge paid is Rs. $$310$$(i) What are the fixed charges and charge per km?(ii) How much does a person have to pay for travelling a distance of $$25km$$?

Solution

## (i) Let the fixed be $$Rs.X$$ and charge per $$km=y$$$$x+10y=220$$    ......(1)$$x+15y=310$$     .......(2)__-____-_____________       $$+5y=90$$                      $$y=18$$(ii) for $$25km$$$$=x+25y$$$$\Rightarrow 40+25(18)$$ $$=Rs.490$$Maths

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