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Question

The taxi charges in Hyderabad are fixed, along with the charge for the distance covered. For a distance of $$10km$$, the charge paid is Rs. $$220$$. For a journey of $$15km$$, the charge paid is Rs. $$310$$
(i) What are the fixed charges and charge per km?
(ii) How much does a person have to pay for travelling a distance of $$25km$$?


Solution

(i) Let the fixed be $$Rs.X$$ and charge per $$km=y$$

$$x+10y=220$$    ......(1)

$$x+15y=310$$     .......(2)
__-____-_____________
       $$+5y=90$$
           
           $$y=18$$

(ii) for $$25km$$

$$=x+25y$$

$$\Rightarrow 40+25(18)$$ $$=Rs.490$$

Maths

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