Question

The temperature at which the root mean square velocity of $S{O}_2$ molecules is the same as that of $O_2$ at ${27}^{o}C$ is:

• A. ${600}^{o}C$
• B. ${300}^{o}C$
• C. ${327}^{o}C$
• D. ${27}^{o}C$

Answer 1

Answer: (C)

${327}^{o}C$

$\sqrt{\frac{3RT}{M_{S{O}_2}}}=\sqrt{\frac{3RT}{M_{O_2}}}$
$\frac{T}{64}=\frac{300}{32}$
$T={\frac{300\times 64}{32}}^2$
T = 600 K
$T={327}^{o}C$