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Question

The temperature at which the root mean square velocity of $$SO_2$$ molecules is the same as that of $$O_2$$ at $$27^o C$$ is:


A
600oC
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B
300oC
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C
327oC
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D
27oC
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Solution

The correct option is B $$327^oC$$
$$\sqrt{\dfrac{3 RT}{M_{SO_2}}} = \sqrt{\dfrac{3 RT}{M_{O_2}}}$$
$$\dfrac{T}{64} = \dfrac{300}{32}$$
$$T = \dfrac{300 \times 64}{32}^2$$
T = 600 K
$$T = 327^o C$$

Chemistry

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