Question

# The temperature at which the root mean square velocity of $$SO_2$$ molecules is the same as that of $$O_2$$ at $$27^o C$$ is:

A
600oC
B
300oC
C
327oC
D
27oC

Solution

## The correct option is B $$327^oC$$$$\sqrt{\dfrac{3 RT}{M_{SO_2}}} = \sqrt{\dfrac{3 RT}{M_{O_2}}}$$$$\dfrac{T}{64} = \dfrac{300}{32}$$$$T = \dfrac{300 \times 64}{32}^2$$T = 600 K$$T = 327^o C$$Chemistry

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