Question

The temperature at which the speed of sound becomes double to that at 27${}^o$C is

• A. 273${}^o$C
• B. 0${}^o$C
• C. 927${}^o$C
• D. 1027${}^o$C

Answer 1

The correct option is C 927${}^o$C

$\nu \propto \sqrt{T}$

so, $\frac{2\nu }{\nu }=\sqrt{\frac{T_1}{T_2}}$

$2=\sqrt{\frac{T_1}{273+27}}$

$4\left(300\right)=T_1$

$T_1=1200K$

$=(1200-273{)}^{\circ }C$

$={927}^{\circ }C.$