Question

# The temperature inside a refrigerator is t 2°C and the room temperature is t 1°C. The amount of heat delivered to the room for each joule of electrical energy consumed ideally will be

A
t2+273t1t2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
t1+t2t1+273
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
t1t1t2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
t1+273t1t2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

## The correct option is D t1+273t1−t2Coefficient of Performance of Refrigerator COP=QcW=t2+273t1−t2 We have to find heat given to room per unit electrical energy. Room is at higher temperature and act as hot reservoir. And electrical energy is the input energy shown as W. So, we have to find QHW Again, QH=Qc+W ⟹QHW=QcW+1 =t2+273t1−t2+1 ⟹QHW=t1+273t1−t2

Suggest Corrections
37
Join BYJU'S Learning Program
Related Videos
Thermodynamic Devices
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program