The temperature of $20 L$ of nitrogen was increased from $100 K$ to $300 K$ at a constant pressure, change in volume will be:

80

litres

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60

litres

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40

litres

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20

litres

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Solution

The correct option is C $60$ litres
$\begin{matrix} P_{1} = P_{2} \frac{n R T_{1}}{V_{1}} = \frac{n R T_{2}}{V_{2}} \frac{100}{20} = \frac{300}{V_{2}} V_{2} = 60 L \end{matrix}$
Hence option (B) 60L is correct

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The temperature of 20L of nitrogen was increased from 100K to 300K at a constant pressure, change in volume will be:

The correct option is C 60 litresP1=P2nRT1V1=nRT2V210020=300V2V2=60LHence option (B) 60L is correct

The temperature of $20 L$ of nitrogen was increased from $100 K$ to $300 K$ at a constant pressure, change in volume will be:

The correct option is C $60$ litres
$\begin{matrix} P_{1} = P_{2} \frac{n R T_{1}}{V_{1}} = \frac{n R T_{2}}{V_{2}} \frac{100}{20} = \frac{300}{V_{2}} V_{2} = 60 L \end{matrix}$
Hence option (B) 60L is correct