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Question

The temperature of a gas consisting of rigid diatomic molecules is T = 300 K. Calculate the root mean square velocity of a rotating molecule if its moment of inertia is equal to     I=2.1×1039gcm2.


Correct Answer
A
rad/sec.
Your Answer
B
rad/sec.
Your Answer
C
rad/sec.
Your Answer
D
rad/sec.

Solution

The correct option is A rad/sec.
Let ωρms be the angular root mean square velocity
12Iω2ρms=22kTωrms=(2kTI)=[2×(1.38×1023)×300(2.1×1046)][ΘI=2.1×1039gcm2=2.1×1046kgm2]=6.3×1012rad/sec.

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