Question

# The temperature of a gas consisting of rigid diatomic molecules is T = 300 K. Calculate the root mean square velocity of a rotating molecule if its moment of inertia is equal to     I=2.1×10−39gcm2.

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Solution

## The correct option is A rad/sec.Let ωρms be the angular root mean square velocity 12Iω2ρms=22kTωrms=√(2kTI)=√[2×(1.38×10−23)×300(2.1×10−46)][ΘI=2.1×10−39gcm2=2.1×10−46kgm2]=6.3×1012rad/sec.

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