CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The term independent of x in the expansion of (6x13x)9 is equal to:

A
9C3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
9C3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
9C2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
none of the above
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 9C3
Given
(6x13x)9

General term of given expansion is
Tr+1=9Cr(x)9r61(x)r3(1)r

Tr+1=9Cr(x)93r6(1)r(1)

Comparing terms having power x0 with Tr+1=9Cr(x)93r6(1)r we get

93r6=0r=3
Hence coefficient of term having term x0 is 9C3(1)3=9C3


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Visualising the Coefficients
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon