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Question

The term without x in the expansion of (2x12x2) is



A

495

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B

-495

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C

-7920

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D

7920

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Solution

The correct option is B

7920


Suppose the (r+1)th term in the given expansion is independent of x.

Then, we have:

Tn+1=12Cr(2x)12r(12x2)r

=(1)r12Cr2122rx12r2r

For this term to be independent of x, we must have:

12-3r =0

r=4

Required term:

(1)412C42128

=12×11×10×94×3×2×16

=7920


Mathematics
RD Sharma
Standard XI

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