Question

# The time period of small oscillations of a uniform rod of length L pivoted about one end and oscillating in a vertical plane is T1  and time period of a simple pendulum of same length L is T2 .  The ratio T1T2  is

A
23
B
13
C
23

D
34

Solution

## The correct option is B √34x=x0 sin2 ωt=x02(1−cos 2ω t)=x02−x02cos 2ω t Frequency ω′=2ω ⇒2πT′=2ω⇒T′=(πω)Amplitude = x02

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