The top surface of a sweet is in the form of a parallelogram. Length of the base is equal to 4 cm and the height is equal to 3 cm. Find the area of the top surface which is in the form of a parallelogram.

12 cm²

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24 square cm.

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18 square cm.

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26 square cm.

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Solution

The correct option is A
12 cm²

$Area of parallelogram = b a s e \times h e i g h t Area of top surface of the sweet (parallelogram) = (4 \times 3) c m^{2} = 12 c m^{2}$

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The top surface of a sweet is in the form of a parallelogram. Length of the base is equal to 4 cm and the height is equal to 3 cm. Find the area of the top surface which is in the form of a parallelogram.

The correct option is A 12 cm2 Area of parallelogram=base×heightArea of top surface of the sweet (parallelogram)=(4×3) cm2=12 cm2

The correct option is A
12 cm²

$Area of parallelogram = b a s e \times h e i g h t Area of top surface of the sweet (parallelogram) = (4 \times 3) c m^{2} = 12 c m^{2}$