Question

# The total energy of a simple harmonic oscillator is proportional to

A
amplitude
B
square of amplitude
C
frequency
D
velocity

Solution

## The correct option is B square of amplitudeIn SHM, the total energy is $$E = \frac{1}{2}m \omega^2 A^2$$where the symbols have their usual meanings.$$E \propto A^2$$Physics

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