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Question

The total energy of an artificial satellite of mass m revolving in a circular orbit around the earth with.a speed v is


A
12mv2
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B
14mv2
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C
14mv2
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D
mv2
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E
12mv2
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Solution

The correct option is E $$-\dfrac {1}{2} mv^2$$
$$\because$$ Total energy of the satellite is
$$E= -\dfrac {1}{2}\dfrac {GM_em}{R_e}$$
where $$K=\dfrac {1}{2}\dfrac {GM_em}{R_e}$$
$$\therefore $$ Total energy = Kinetic energy
$$ K=-\dfrac {1}{2}mv^2$$
Putting the value of KE in the form of mass of a satellite (m) and speed (v).

Physics

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