CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The total number of possible isomers for squar-planar [Pt(Cl)(NO2(NO3SCN)]2 is:

A
8
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
12
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
16
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
24
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 12
This complex is of the form Mabcd which has the following isomers
But carefully observing the complex
Im SC¨N both S and n can donate lp
Im NO2 both N and O can donate lp
Thus, the total number of isomers will be (2×2)×3=12
due to SCN: duce to NO2

1194130_1309397_ans_87756b77cf23452daf83e686d5a4261d.jpg

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Position Isomerism
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon