Question

The total number of shared electrons in the lewis dot structure of a $O_2$ molecule is .

• A. four
• B. two
• C. six
• D. three

Answer 1

The correct option is A four

The electronic configuration of an oxygen atom is 2,6; hence, it has 6 valence electrons.
It combines with another oxygen atom to form an oxygen $\left(O_2\right)$ molecule.
During this, '2 electron pairs', i.e., '4 electrons' are shared between the two atoms.
In the given diagram, the shared pairs of electrons are represented as crosses and the rest of valence electrons as dots in the lewis dot structure.