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Question

The total number of ways in which a 5 digit number divisible by 3 can be formed from the digits 0,1,2,3,4,5 without repetition is?
  1. 245
  2. 345
  3. 315
  4. 310
  5. 216


Solution

The correct option is E 216

option (c )

Divisibility test for 3- sum of digits should be divisible by 3.

Case 1:- When 0 is not included sum = 15 divisible by 3

Number of combinations = 5! = 120

Case 2:- When 3 is not used. Sum = 12 divisible by 3

Number of combinations - 4.4..3.2 =96

Total = 120+96= 216

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