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The total vapour pressure of a mixture of 1 mol A (P0A=130 torr) and 2 mol B(P0B=240 torr) is 200 mm. In this case:
  1. There is no deviation from Raoult's Law
     
  2. There is positive deviation from Raoult's Law
  3. Molecular masses of A and B are also required
  4. There is negative deviation from Raoult's Law


Solution

The correct option is D There is negative deviation from Raoult's Law
Ptotal=P0A×A+P0B×B

=203.33mm>200mm
Vapour pressure decreases.
Hence, there is an observed negative deviation from Raoult's Law.

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