1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# The total vapour pressure, Ptotal (in torr) for a mixture of two volatile components, A and B is given byPtotal =220−110 XBWhere, XB is mole fraction of component, B in mixture. Hence, pressure (in torr) of pure components, A and B are respectively:

A
220,110
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
110,220
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
220,330
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
220,150
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is A 220,110Ptotal=220−110XBIf XB=1 i.e., XA is absent, pure BPtotal:220−110×(1)=220−110P0B=110 unitsNow;If XB=0 i.e., XB is absent, pure APTotal=220−110×(0)P0A=220 units∴P0A=220 torr; P0B=110 torr.

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Stoichiometric Calculations
CHEMISTRY
Watch in App
Join BYJU'S Learning Program