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Question

The transformer with efficiency 80%works at 4kw and 100V. If the secondary voltage is 200 V then the primary and secondary currents are respectively? 


Solution

given n=80%
Ep=100v
EpIp=4kw
        =4000w
Ip=Ep.Ip/Ep
    =4×1000/100
    =40A
Is=80×100×40/200×100
  =16 A


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